Recent Posts

Pages: [1] 2 3 4
Aptitude Lectures / Re: Time and Work Lecture Series
« Last post by priyanka karanam on June 26, 2014, 06:32:33 AM »
I have doubt in one problem can u help mee.................
Q:if 3men or 5boys can do a work in 86days,how long would 12men and 11boys take to complete the work
Partnership / Re: Partnership
« Last post by Shachi on June 26, 2014, 05:00:45 AM »
We calculating the ratio for 12 months
A's contribution= 50000*12
since B left x months before the end of the year so his contribution=60000(12-x)
and same for C= 70000(12-x)
their ratios
    =>    60  : 6(12-x)   : 7(12-x)
Now given ratio is 20:18:21
so we divide by 3 in the ratio
    =>    20  : 3(12-x)   : 7(12-x)/3
on comparing the B's ratio with the given one we get
Time and Work / Re: Time and Work Problem
« Last post by Shachi on June 24, 2014, 05:07:34 AM »
if A and B works together then they complete the work in 12 days

                     1/A+1/B=1/12------>(eqn 1)

if B and C works together then they complete the work in 20/3 days

                      1/B+1/C=3/20------>(eqn 2)
A works for 3 days and B works for 4 days and C works for 7 days so the equation for this


Substitute the value of 1/A and 1/C  from equation 1 and 2 then we get,
now put 1/B=1/20 in equation 1 so we get,
that means A alone can complete the work in 30 days.                   
Time and Work / Time and Work Problem
« Last post by samuel dhas on March 21, 2014, 10:18:18 PM »
Hello from Samuel.....   I need answer to this question...

A and B can do a work in 12 days, while B and C can do the work in 6 2/3 days. After A had worked on it for 3 days and B for 4 days, C finished the work in 7 days.
In how may days can A alone complete the work?
Post your Aptitude Problem / CALENDERS
« Last post by Bibhudas on March 14, 2014, 07:55:18 AM »
Hey Daniel!
I am posting my problem here just try to rectify my mistake :D

what should was the day for 25th december 1995?
start with 1600 years,which has 0 odd days
 300 years has 1 odd day
for 94 years ,we 94/4=23 as quotient and 2 as reminder, my doubt is that is 23 gives the no of leap year?
like in 100 years if 100/4=25 is quotient as everyone knows but there is 24 leap years.
please explain it.
thank you
General Discussion / any one tell me the solution
« Last post by Dhivya on March 11, 2014, 09:47:04 AM »
Imagine we have a large string like this "ABCBAHELLOHOWRACECARAREYOUIAMAIDOINGGOOD" which contains multiple palindromes within it, like ABCBA, RACECAR, ARA, IAMAI etc... Now write a method which will accept this large string and return the largest palindrome from this string. If there are two palindromes which are of same size, it would be sufficient to just return any one of them.
Aptitude Lectures / Re: Time and Work Lecture Series
« Last post by minnu on March 08, 2014, 04:20:23 AM »
please solve more problems of each topic ....
Pipes and Cisterns / Re: PIPES AND CISTERN PROB
« Last post by aptiadmin on March 02, 2014, 12:20:23 AM »
Hey Kumar :) This is a really good problem :) 8) Im not really sure if my solution is right :) But this is what I think :)

Alright so Pipe A takes 16 min to fill a tank. Now Pipe B and C have cross sectional circumferences in ratios 2:3 .. Circumferences means 2*pi*r  .
However when talking about pipes, we are interested in flow per unit area. Meaning the AREA is important for us. So since we know that
Area = pi*r*r , we will have to square the ratios to get the actual area ratios. Hence in terms of Area, B and C have cross sectional areas in the ratio 4 :9 .

But they've given that A has a one third circumference of C. So the ratio can be 1:3 ...Now combining all these statements we can say that the

Ratios of Circumference of A: B :C = 1 : 2 : 3

AND Ratios of Area of A : B : C = 1 :4 :9  :o

So that means Pipe B fills tank 1,  4 times faster than Pipe A &
Pipe C fills tank 1, 9 times faster than Pipe A.

Now coming to the 2nd tank... we know that Since its twice as big as the first, A will take 32 min to fill this tank right ?

So every min, Pipe A would have to do  (1/32) of the work :)

But Pipe B and Pipe C will together do the work 13 ( 4 + 9) times faster than Pipe A.

So every minute, Pipe B and C do 13 * ( 1/32) = 13/32 of the work.

So basically if we Invert this by "RULE of FLIP", then we know that Pipe B & C will take (32/13) mins or Just under 2.5 mins to fill the tank together :)

Once again, Im not really sure of this solution :) But Im pretty sure this is the way to approach this problem :)

Hopefully we can discuss this a little further and find whether the solution is right or no :) ;D
Pipes and Cisterns / PIPES AND CISTERN PROB
« Last post by kumar halijol on February 28, 2014, 01:32:20 AM »
Q1. Pipe A takes 16 min to fill a tank. Pipes B and C, whose cross-sectional circumferences are in the ratio 2:3, fill
another tank twice as big as the first. If A has a cross-sectional circumference that is one-third of C, how long will
it take for B and C to fill the second tank? (Assume the rate at which water flows through a unit cross -sectional
area is same for all the three pipes.

plz provide soln this problem
Pipes and Cisterns / Re: PIPES AND CISTERNS (capacity of cistern)
« Last post by aptiadmin on February 22, 2014, 09:50:29 PM »
Hello Guys :)  Bibhu you posted the right answer buddy :)   8) great job! :) i hope Mohd's doubt is cleared now :)
The more questions we discuss the more we can learn :)
Pages: [1] 2 3 4