So the Rotten Apples Problem goes like this :
A box containing a dozen apples is opened and a few of the apples are found to be rotten. Which of the following may be the ratio of fresh apples to rotten apples ?
a). 4 : 7
b). 3: 1
c). 5 : 3
d).3 : 2
This problem should take you five seconds. Not more
Understand this : In Ratio problems like these, add all the ratios and see if it adds up to the total number or any of the factors of the total number. Here the total number is 12(because a dozen of apples)
See option a) … 4 + 7 = 11 …11 is not a factor of 12.
Similarly even c) and d) will fail. But option b) .. 3+1 = 4 which is a factor of 12 Hence b)3 : 1 is the right answer
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The Chocolate Trouble Problem is as shown below :
3 friends : Nikhil, Santosh and Jeya have 93 chocolates among them. They decide to divide up the chocolates in the ratio
(1/2) : (1/3) : (1/5) . How many chocolates did Santosh get ?
The simplest way to solve this problem is to first simplify the ratios. If you keep them as fractions you can get confused and end up making a mistake.
So now taking the LCM of the denominators we can say that : LCM of 2,3 and 5 is 30.
Multiply this to all the ratios to retain their relative values. So the new ratios will be
(30 X 1/2) : (30 X 1/3) : (30 X 1/5)
15 : 10 : 6
So now Santosh’s share will be 10/(15+10+6) of the total chocolates = (10/31)
Hence no of chocolates Santosh gets = (10/31) X 93 = 10 X 3 = 30 chocolates :)
One of those questions that take like 5 seconds to solve 😉 The Ages Increase Simple Problem is as shown below :
Present ages of X and Y are in the ratio 5:6 respectively.Seven years hence this ratio will become 6:7 respectively.
what is X’s present age in years?
c)Cannot be determined
d)None of these
Solution : The Solution can be found at : http://aptitudeacademy.co.in/forum/index.php?topic=18.0