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The Chocolate Trouble Problem is as shown below :

Question :

3 friends : Nikhil, Santosh and Jeya have 93 chocolates among them. They decide to divide up the chocolates in the ratio

(1/2) : (1/3) : (1/5) . How many chocolates did Santosh get ?

Answer :

The simplest way to solve this problem is to first simplify the ratios. If you keep them as fractions you can get confused and end up making a mistake.

So now taking the LCM of the denominators we can say that : LCM of 2,3 and 5 is 30.

Multiply this to all the ratios to retain their relative values. So the new ratios will be

(30 X 1/2) : (30 X  1/3) : (30 X 1/5)

15 : 10 : 6

So now Santosh’s share will be 10/(15+10+6)  of the total chocolates = (10/31)

Hence no of chocolates Santosh gets = (10/31) X 93 = 10 X 3 = 30 chocolates :)

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One of those questions that take like 5 seconds to solve 😉 The Ages Increase Simple Problem is as shown below :

Question :

Present ages of X and Y are in the ratio 5:6 respectively.Seven years hence this ratio will become 6:7 respectively.
what is X’s present age in years?

a)35
b)42
c)Cannot be determined
d)None of these

Solution :  The Solution can be found at : http://aptitudeacademy.co.in/forum/index.php?topic=18.0

If you want any questions solved, you can make an account on the Forum and Post it there! CHEERS!

The Tank not empty Problem sent in by one of our readers is as shown below

Question :

Q):A water tank is two-fifth full. pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open,how long will it take to empty or fill the tank completely?
a)6min. to empty
b)6min. to fill
c)9min. to empty
d)9min. to fill

Solution : 

For the solution You can read the forum thread  –  http://aptitudeacademy.co.in/forum/index.php?topic=14.0