## Cricket Set Cost Problem

The Cricket Set Cost Problem is as follows :

Question:   The coach of a cricket team buys 3 bats and 9 balls for Rs 3900.

Later, he buys another bat and 2 more balls of the same kind for Rs 1200.

Find the price of a bat and a ball?

Answer:   Let the price of a bat be Rs x and that of a ball be Rs y.

It is given that 3 bats and 9 balls are bought for Rs 3900.

So,   3x+9y=3900  ………………… (1)

and it is given that one bat and 2 balls of the same kind cost Rs 1200.

That is,  x+2y=1200  …………….. (2)

=> x=1200-2y  …………………….(3)

putting this value in equation (1), we get

3(1200-2y) +9y=3900

=> 3600-6y+9y=3900

=> 9y-6y=3900-3600

=> 3y= 300

=> y=300/3

=> y=100

Hence Ball = 100 Rs

Putting the value of y in equation (3)

x=1200-2y

x=1200-2*100

x=1200-200

x=1000

Hence Bat = 1000 Rs.

So, the cost of the Bat is Rs.1000 and the Ball is Rs.100 ## Pencil Eraser Cost Problem

The Pencil Eraser Cost Problem is given below

Question:

Romila went to a stationary stall and purchased 2 pencils and 2 erasers for Rs 8.
Her friend Sonali saw new variety of pencils and erasers with Romila, and she also bought 4 pencils and 6 erasers for Rs 18.
Find the cost of a pencil and an eraser?

Let the cost of a pencil be Rs x and the cost of an eraser be Rs y.

It is given that Romila purchased 2 pencils and 2 erasers for Rs 8.

So,  2x+2y=8

=> x+y=4    ……………. (1)

=> x=4-y    …………….. (2)
It is also given that Sonali purchased 4 pencils and 6 erasers for Rs 18.

That is,  4x+6y=18

=> 2x+3y=9  …………. (3)

putting the value of equation (2) into equation (3), we get

2(4-y)+3y=9

=> 8-2y+3y=9
=> 3y-2y=9-8
=> y=1

put the value of y in equation (2),

x=4-y
=> x=4-1
=> x=3

The cost of a pencil is Rs 3 and the cost of an eraser is Rs 1.

Got a question ? Leave me a COMMENT AND ILL GET BACK TO YOU! ## Father Son Ages Problem with Solution

The father son ages problem with solution is as follows :

Ques. A Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
A. 2 times B.
 2 1 times 2
C.
 2 3 times 4
D. 3 times

SOLUTION : The solution to the above problem is shown below  (4x + 8) = 5/2 (x + 8) 8x + 16 = 5x + 40 3x = 24 x = 8.