The Cricket Set Cost Problem is as follows :
Question: The coach of a cricket team buys 3 bats and 9 balls for Rs 3900.
Later, he buys another bat and 2 more balls of the same kind for Rs 1200.
Find the price of a bat and a ball?
Solved Aptitude Problems
Answer: Let the price of a bat be Rs x and that of a ball be Rs y.
It is given that 3 bats and 9 balls are bought for Rs 3900.
So, 3x+9y=3900 ………………… (1)
and it is given that one bat and 2 balls of the same kind cost Rs 1200.
That is, x+2y=1200 …………….. (2)
=> x=1200-2y …………………….(3)
putting this value in equation (1), we get
=> 3y= 300
Hence Ball = 100 Rs
Putting the value of y in equation (3)
Hence Bat = 1000 Rs.
So, the cost of the Bat is Rs.1000 and the Ball is Rs.100
The Pencil Eraser Cost Problem is given below
Romila went to a stationary stall and purchased 2 pencils and 2 erasers for Rs 8.
Her friend Sonali saw new variety of pencils and erasers with Romila, and she also bought 4 pencils and 6 erasers for Rs 18.
Find the cost of a pencil and an eraser?
Let the cost of a pencil be Rs x and the cost of an eraser be Rs y.
It is given that Romila purchased 2 pencils and 2 erasers for Rs 8.
=> x+y=4 ……………. (1)
=> x=4-y …………….. (2)
It is also given that Sonali purchased 4 pencils and 6 erasers for Rs 18.
That is, 4x+6y=18
=> 2x+3y=9 …………. (3)
putting the value of equation (2) into equation (3), we get
put the value of y in equation (2),
The cost of a pencil is Rs 3 and the cost of an eraser is Rs 1.
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The father son ages problem with solution is as follows :
||A Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
SOLUTION : The solution to the above problem is shown below
Answer: Option (A)
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
||(4x + 8) =
||(x + 8)
8x + 16 = 5x + 40 3x = 24
x = 8.
|Hence, required ratio =
||(4x + 16)/(x + 16)
|| = 2