The father son ages problem with solution is as follows :
Ques.  A Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?  

SOLUTION : The solution to the above problem is shown below
Answer: Option (A)
Explanation:
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
(4x + 8) =  5/2  (x + 8) 
8x + 16 = 5x + 40 3x = 24
x = 8.
Hence, required ratio =  (4x + 16)/(x + 16)  =  48/24  = 2 