The father son ages problem with solution is as follows :
| Ques. | A Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age? | |||||||||||||||
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SOLUTION : The solution to the above problem is shown below 
Answer: Option (A)
Explanation:
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5/2 | (x + 8) |
8x + 16 = 5x + 40 3x = 24
x = 8.
| Hence, required ratio = | (4x + 16)/(x + 16) | = | 48/24 | = 2 |