The father son ages problem with solution is as follows :
|Ques.||A Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?|
SOLUTION : The solution to the above problem is shown below
Answer: Option (A)
Let Ronit’s present age be x years. Then, father’s present age =(x + 3x) years = 4x years.
|(4x + 8) =||5/2||(x + 8)|
8x + 16 = 5x + 40 3x = 24
x = 8.
|Hence, required ratio =||(4x + 16)/(x + 16)||=||48/24||= 2|