Square Rectangle Perimeter Problem Solution

The Square Rectangle Perimeter Problem is as follows :

Consider that a square and a rectangle have the same area. Now if the perimeter of the square is x1 and the perimeter of the rectangle is x2, then which of these relations holds true ?

a). x1 = x2

b). x1 < x2

c). x1 > x2

d). None of these

square-rectangle problem

square-rectangle problem


The answer is given below :


Consider a square and a reactangle. Lets say that their areas are equal and are 16 sq.cm .

So the sides of the square will be 4 cm each.

And lets say the side of the rectangle is 2cm height and 8cm wide.

So if you consider the perimeter of the square i.e x1 = 4 + 4 + 4 + 4= 16cm

However if you calculate the perimeter of the rectangle, i.e x2 = 8 + 2 + 8 + 2 = 20cm.

Hence we see that the perimeter of the rectangle is more than that of the square,

So the answer is (b) x1 < x2  :) 

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