The Square Rectangle Perimeter Problem is as follows :
Consider that a square and a rectangle have the same area. Now if the perimeter of the square is x1 and the perimeter of the rectangle is x2, then which of these relations holds true ?
a). x1 = x2
b). x1 < x2
c). x1 > x2
d). None of these
square-rectangle problem
The answer is given below :
EXPLANATION :
Consider a square and a reactangle. Lets say that their areas are equal and are 16 sq.cm .
So the sides of the square will be 4 cm each.
And lets say the side of the rectangle is 2cm height and 8cm wide.
So if you consider the perimeter of the square i.e x1 = 4 + 4 + 4 + 4= 16cm
However if you calculate the perimeter of the rectangle, i.e x2 = 8 + 2 + 8 + 2 = 20cm.
Hence we see that the perimeter of the rectangle is more than that of the square,
So the answer is (b) x1 < x2 
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