The Square Rectangle Perimeter Problem is as follows :

**Consider that a square and a rectangle have the same area. Now if the perimeter of the square is x1 and the perimeter of the rectangle is x2, then which of these relations holds true ?**

**a). x1 = x2**

**b). x1 < x2**

**c). x1 > x2**

**d). None of these**

The answer is given below :

**EXPLANATION :**

Consider a square and a reactangle. Lets say that their areas are equal and are 16 sq.cm .

So the sides of the square will be 4 cm each.

And lets say the side of the rectangle is 2cm height and 8cm wide.

So if you consider the perimeter of the square i.e x1 = 4 + 4 + 4 + 4= 16cm

However if you calculate the perimeter of the rectangle, i.e x2 = 8 + 2 + 8 + 2 = 20cm.

Hence we see that the perimeter of the rectangle is more than that of the square,

So the answer is **(b) x1 < x2 **

Leave a comment below if you found this useful